(01/27/2008 08:25:01 PM) Greg: I do not get this.
(01/27/2008 08:26:16 PM) Greg: An elevator cab has a total run of 190 m. Its maximum speed is 305 m/min and its (constant) acceleration is 1.22 m/s^2. How long does it take to make the run, starting a nd ending at rest?
(01/27/2008 08:27:36 PM) Greg: If its acceleration is constant, how does it get back to rest?
(01/27/2008 08:32:13 PM) Larry: well, they mean during the period of starting and ending it's constantly accelerating 
(01/27/2008 08:33:32 PM) Larry: and well
(01/27/2008 08:33:46 PM) Larry: does it say if it's traveling in the upward direction or down?
(01/27/2008 08:33:51 PM) Larry: any diagrams?
(01/27/2008 08:33:51 PM) Greg: nope
(01/27/2008 08:34:08 PM) Larry: that REALLY helps
(01/27/2008 08:34:15 PM) Larry: in elevator problems
(01/27/2008 08:34:19 PM) Larry: </sarcasm>
(01/27/2008 08:34:39 PM) Larry: sideways?
(01/27/2008 08:34:40 PM) Larry: heh
(01/27/2008 08:35:09 PM) Larry: it just accelerates, coasts and negatively accelerates  
(01/27/2008 08:35:14 PM) Larry: okay I'll stop talking to myself
(01/27/2008 08:37:07 PM) Larry: well...what don't you get? calculate the time it takes to get to the cruising speed and how far it would travel in that time using v=at and d=1/2at^2
(01/27/2008 08:40:30 PM) Larry: anyway, I think you face that common misconception...largely caused by not fully knowing conceptual physics(maybe you just forgot, I don't blaim you). it speeds up to the cruising speed, then coasts with zero acceleration, then decelerates with the same acceleration as before, until it stops
(01/27/2008 08:40:47 PM) Larry: to my understanding, that's how it functions 
(01/27/2008 08:41:04 PM) Larry: do you 'get it' now?
(01/27/2008 08:45:39 PM) Greg has signed off.
(01/27/2008 08:49:43 PM) Greg has signed on.