#include <stdio.h>
#include <stdlib.h>

int main() {
	char * cp = 0;
	unsigned int * uip = 0;
	unsigned int cp_size = sizeof(char *) * 8;
	unsigned int uip_size = sizeof(unsigned int *) * 8;

	printf("\n");

	if (  cp = (char *)malloc( cp_size )  ) {
	 printf(" malloc #1 succeeded, start is %u, size %u\n", &cp, cp_size);
	} else {
	 printf(" malloc #1 failed!\n");
	}

	if (  uip = (unsigned int *)malloc( uip_size )  ) {
	 printf(" malloc #2 succeeded, start is %u, size %u\n", &uip, uip_size);
	} else {
	 printf(" malloc #2 failed!\n");
	}

	if ( cp ) { free(cp); }
	if ( uip ) { free(uip); }

	printf("\n");
	return 0;
}

/*
    output on my system is:

        malloc #1 succeeded, start is 3217024436, size 32
        malloc #2 succeeded, start is 3217024432, size 32

Q: Why does malloc #2 OVERLAP #1?
Do I need to somehow "lock" my malloc-allocated memory?
Any help would be greatly appreciated.

*/