[01:40] Session Ident: MU7C_Ronaldo (SwiftIRC, Hiitsnick) (~MU7C_Rona@Swift-1E85A1EC.jetstream.xtra.co.nz) [01:40] To prove C(F(C)) = C [01:40] C(f) = 5/9 f - 160/9 [01:40] replace f with F(C) [01:40] C(f) = 5/9 F(C) - 160/9 [01:40] but F(C) = 9/5C +32 [01:40] So, C(f) = 5/9 (9/5C +32) - 160/9 [01:40] C(f) = C + 160/9 - 160/9 [01:40] C(f) = C Session Close: Fri Sep 18 03:28:18 2009 Session Start: Tue Sep 29 22:50:20 2009 Session Ident: MU7C_Ronaldo [22:50] Session Ident: MU7C_Ronaldo (SwiftIRC, Hiitsnick) (~MU7C_Rona@2F7E7A0A.EBC88A9D.C88A0069.IP) [22:50] talk here 15[22:51] i fuckin love u ronaldo 15[22:54] you will help me ? [22:57] ask lol 15[22:57] omg hawt [22:57] what trig-,- [22:57] i might not knokw, but ask first 15[22:57] convert each angle to a decimal in degrees 15[22:58] 61 degrees 42' 21" [22:59] sorry dc'ed [22:59] could you ask again? 15[22:59] convert each angle to a decimal in degrees 15[22:59] 61 degrees 42' 21" 15[23:02] ne ideas> [23:03] so sorry but dc'ed again 15[23:04] haha [23:04] err 61'42'21"" 15[23:04] convert each angle to a decimal in degrees [23:04] right? 15[23:04] ya [23:04] well it is just 61 + 42/60 + 21/3600 15[23:04] 61 degrees 41 minutes 21 seconds 15[23:04] sumthin like that [23:04] (16:04:13) well it is just 61 + 42/60 + 21/3600 [23:04] ( 15[23:06] wait 15[23:07] does it have to be in degrees to turn to decimal or wut [23:08] x'y'z" ---> x + y/60 + z/3600 [23:08] so 61'42"21" is just 61.7058333 [23:09] 1 degree has 60minutes, 1 mintues has 60 seconds:P [23:13] here? 15[23:13] ya [23:13] got that? 15[23:13] so thats pretty easy then ? [23:14] well are you allowed to use calculator? 15[23:19] ya lol 15[23:19] its homework 15[23:19] but idk how to do the second angle thing 15[23:19] i got a couple more like that so im just doin it 15[23:21] do u know how to convert angles to DMS ? 15[23:25] cuz im pretty sure u gotta do it a different way than just *60 15[23:26] 61.24 = 61 14 24 question mark ? [23:26] oh [23:27] 0.24*3600 [23:27] =864 15[23:27] que ? [23:27] 864/60=14.4 15[23:27] dont u do .24*60 ? [23:27] actually wait 15[23:27] and get 14.4 [23:27] start again 15[23:27] and then do .4 * 60 15[23:27] and get 24 ? [23:27] 0.24*60=14.4 15[23:27] ya [23:28] 0.4*60=24 [23:28] 0.4 is from 14.4 take off 14 15[23:30] ya 15[23:30] so its 61 14 24 ? 15[23:30] correct ? 15[23:33] RONALDINHO [23:34] sorry dc'ed again [23:34] lol 15[23:34] so its 61 14 24 ? 15[23:34] YES? [23:35] yea 15[23:38] what if i have 39.6 for seconds 15[23:38] do i just round it 15[23:39] 29.411 = 7.411*60 = 0724.66 , 7.66*60 = 0739.6 [23:40] if it is exact value [23:40] then why round 15[23:40] well can u have a 39.6 as seconds 15[23:40] or not ? [23:41] i guess? [23:41] unelss there is a smaller unit than seconds Session Time: Wed Sep 30 00:00:10 2009 15[00:15] 135 degree angle 15[00:15] and 30 foot radius 15[00:15] = how much area ? [00:15] -,- [00:15] ok [00:16] what's the area of a full circle 30foots radius [00:16] hello? [00:16] i am helping 15[00:16] umm 15[00:17] 2826 [00:17] well 2827=.= [00:17] any way its 30 times 30 times pi right?> 15[00:17] ya [00:17] so how many degree in a circle-,- 15[00:18] 071,060.125  ? [00:18] well yea i got 1060.287521 but close enough [00:19] what you do is just to find area of full circle [00:19] devided by 360 then degrees [00:19] or devided by 2 pi if radian * whatever value 15[00:19] ya lol [00:19] why ask me then [00:19] so easy [00:19] lol 15[00:19] idk lol i forgot for a minute [00:20] xd 15[00:22] do u know angular speed and linear speed? [00:22] omega and shit? [00:22] physics 15[00:23] its like traveling around a circle with a radius of 5 cm and in 20 seconds 1/3 radians is swept out, whats angular speed + linear speed [00:24] is that the actually question? 15[00:24] ya [00:25] ok [00:25] angular speed is easy [00:25] 1/3 rad in 20seconds so, 1/3 over 20 is 1over60 rad per sec [00:26] linear.....err , circumference of a circle radius 5 is 2*5*pi [00:26] 10 pi over 2pi times 1/3 pi is [00:27] 5over 3 pi [00:27] that's in 20seconds [00:27] so 5 over 60 cm per sec or 1over 12 cm per sec [00:29] harro? 15[00:30] it says [00:30] says what 15[00:30] linear speed = distance traveled divided by time it took to travel that distance [00:31] (17:25:55) linear.....err , circumference of a circle radius 5 is 2*5*pi [00:31] whcih is 10pi [00:31] (17:26:24) 10 pi over 2pi times 1/3 pi is [00:31] (17:26:56) 5over 3 pi [00:31] you know whole cricle is 2pi, you only ewnt over 1.3 pi [00:31] 1/3pi [00:31] radian 15[00:31] o oook ook 15[00:33] howd u go from 5/3 pi , in 20 seconds to , 5/60 cm per second ? 15[00:34] o just 15[00:34] o ok i see [00:34] lol [00:34] 5over 3 times 1 over 20 [00:34] so 5 over (3*20) [00:34] sorry if i am too fast [00:34] or sorry if it isn't the way that your teacher uses [00:34] coz last time you said your teacher way is much easier lol [00:35] my way is to make you understand step by step kinda 15[00:35] lol 15[00:35] im dum for not realizin that [00:35] lol 15[00:35] like after i ask u a question im like 15[00:35] oh nvm im dumb [00:35] lol 15[00:35] sin < 0, cos > 0 15[00:35] name the quadrant in which the angle lies ? [00:36] full question pl0x 15[00:36] that is the full question lol [00:36] sin <0 OR sin x < 0 15[00:36] it says , [00:36] oh nvm same thign really [00:36] lol 15[00:36] so i fink both ? 15[00:36] ya lol [00:37] genereal solution or just 1? [00:37] general* 15[00:37] it says like which quadrant 15[00:37] does the angle lie 15[00:37] on a graph [00:37] oo quadrant [00:37] easy [00:37] you know what quadrants are? 15[00:38] ya [00:38] first quadrant is 0 to pi over 2 15[00:38] like top right, bottom right 15[00:38] o wut [00:38] 2nd is pi over 2 to pi [00:38] etc 15[00:38] WUT 15[00:38] i guess not 15[00:38] teacher went over it 15[00:38] sounded like jibberish to me [00:38] ok same thing [00:39] top right, is first quadrant, in radians , it is zero to pi over 2 [00:39] top left, 2nd quadrant in radians, it is pi over 2 to pi 15[00:39] last time i did radians was 4 yrs ago tbh >.> [00:39] bottom left, 3rd quadrant, pi to 3pi over 2 [00:39] bottom right, 4th quadrant, 3pi over 2 to 2 pi 12[00:40] ok so back to the questoin (17:35:43) sin < 0, cos > 0 15[00:40] its 1st quadrant? [00:40] no ok when is sin of an angle small than zero-,- [00:41] well i will tell you-,- 15[00:41] never ? [00:41] sin x is small than 0 when x is pi to 2pi [00:41] that's the 3rd and 4th quadrant 15[00:41] why is that [00:41] wtf.................. [00:42] you know how a sine graphs loosk like? 15[00:42] the bumps 15[00:42] /\/\/\/\ [00:42] nooooooo 15[00:43] im a fuckin downie [00:43] http://upload.wikimedia.org/wikipedia/commons/thumb/b/b6/Taylorsine.svg/300px-Taylorsine.svg.png [00:44] ignore the purple line 15[00:44] o fuck man 15[00:44] thats been like so long 15[00:44] since i seen that thing [00:44] anyway [00:44] sin 0 is 0 [00:44] then it goes up to 1 at sin (pi over 2) [00:45] then back down to 0 at sin (pi) [00:45] then further down to negative one at sin (3pi over 2) [00:45] then up back to 0 at sin (2pi) [00:45] then repeat 15[00:46] and which points on this graph is Pi/2 and 15[00:46] the first climax after 0 ? 15[00:46] kk lol i got it [00:47] yep 15[00:47] so like 15[00:47] the answer is 3rd + 4th quad ? [00:48] not for the whole question, only for sin <0 [00:48] for cos >0 15[00:48] ok [00:48] it is 1st and 4th [00:48] if you know how a cosine graphs looks like-,- 15[00:48] wait 15[00:48] isnt it 3rd and 1st ? 15[00:49] http://www.intmath.com/Trigonometric-graphs/cos.gif [00:49] look carefully [00:49] from 0 to pi over 2 it is >0 [00:49] then from "pi over 2" to "3pi over 2" it is <0 [00:50] and that's across 2 quadrants [00:50] 1 quadrants is every "pi over 2" 15[00:50] how the fuck do u know which quadrant it is wtf .. [00:51] sigh wait 15[00:51] the first quadrant is from 0 to pi/2 ? 15[00:51] o ok 15[00:51] it just looks weird 15[00:51] cuz itsl ike half as big as the others 15[00:52] on this graph 15[00:52] but wouldnt that make it 2nd and 4th 15[00:52] so confused 15[00:57] * Hiitsnick waits [00:57] k i made it clearer for oyu [00:57] wait [00:57] http://img97.imageshack.us/img97/8950/cos.jpg 15[00:57] oooooooooooooooh [00:57] lol-,- 15[00:57] i fot there was only 4 15[00:57] not 8 15[00:58] 2 of each * [00:58] 2pi is arleady 4quadrants [00:58] so obviously 4pi is 8 15[00:58] ok 15[00:58] so anyways answer = 4 [00:58] 4th quadrants, or bottom right [00:59] so my drawing make it clearer for you? lol 15[00:59] yes but i dun c how its " bottom right" if its not a circle lol [01:00] http://upload.wikimedia.org/wikipedia/commons/thumb/c/c9/Unit_circle_angles.svg/720px-Unit_circle_angles.svg.png 15[01:00] omg 15[01:00] ronaldo 15[01:00] so like 15[01:00] lets c 15[01:00] 14500 for tuition [01:00] ignore the corrdinate 15[01:00] 17 credit hours 15[01:00] this class is 3 15[01:01] can i drop my class and hire u as private teacher for 2588$ a semester ? [01:01] lol [01:01] my english suck though 15[01:02] da fk 15[01:02] dude 15[01:02] my teacher [01:02] you can see my stence doens't amke sense sometimes 15[01:02] cant understand her either .. [01:02] sentence& [01:02] lol 15[01:02] i like 15[01:02] sit in class 15[01:02] understand stuff 15[01:02] then get lost 15[01:02] and then go to sleep [01:02] lol [01:02] reason i teach well , is that my teacher is a very good teacher 15[01:02] she goes through stuff like so bad w/o explanation [01:03] she make us understand how everything worsk [01:03] basically 15[01:03] shes like u see dis yes ? make sense rite gud ? [01:03] lol 15[01:03] and she points to the board 15[01:03] and doesnt say like what shes talkin about 15[01:04] and i /cut and hope ronaldo comes on otherwise my grade = F [01:04] lol 15[01:06] so like 15[01:06] when test time comes around 15[01:06] im gonna print off my mirc logs [01:06] lol [01:06] do you actually understand what i did though 15[01:06] ya 15[01:06] rlly dont wanna incorporate the 4 quadrants of a sin / cos graph into a circle though [01:07] lol [01:08] well you gotta 15[01:09] no 15[01:09] i dont got to 15[01:09] so plz dont [01:09] lol [01:09] what ever 15[01:09] but wtf im lookin in the book and it doesnt show anything about the quadrants on the sin / cos graphs 15[01:09] so idk how the fuck anyones supposed to know that [01:10] lol look at thsi [01:10] http://upload.wikimedia.org/wikipedia/commons/8/8e/Sine_and_Cosine_fundamental_relationship_to_Circle_%28and_Helix%29.gif [01:11] it moves, so watch [01:11] watch the first bit, ignore those 3d part 15[01:12] k i did [01:12] you get that? 15[01:12] ya [01:12] sine and cosine graph is kinda from the circle lol 15[01:13] OMG 15[01:13] honestly 15[01:13] nowhere in the book 15[01:13] does it show 15[01:14] the quadrants of the sin graph [01:14] lol 15[01:14] OMG 15[01:14] im gonna die 15[01:14] * Hiitsnick cuts [01:14] i don't know if there are suppose to ahve one [01:14] lol 15[01:15] sin a = 4/5 cos a = 1/2 , find tanget csc, sec, cot [01:15] tanget csc? 15[01:16] tan , csc , sec, cot [01:16] that's easy, if i know what tanget csc mean [01:16] ok csc is cosec? 15[01:16] ya 15[01:16] ive never done cosecant cotangent or secant in my life [01:17] ok [01:17] tan a = sin a / cos a, so 4/5 over 1.2 [01:17] tan a = sin a / cos a, so 4/5 over 1/2 [01:18] that's 8 over 5 or 1.6 [01:18] cosec is 1 over sin , so 1 over 4/5 , that's 5 over 4 or 1.25 [01:18] sec is 1 over cos, so 1 over 1/2 , = 2 15[01:19] wait 15[01:19] i fucked up 15[01:19] sin a = 4/5 and cos a = -3/5 15[01:19] ... sorry [01:19] well jsut substitute back........... [01:19] tan a = sin a / cos a [01:19] csc a is 1/sin a 15[01:20] tan a = 1.3^ ? 15[01:20] 1 1/3 * 15[01:20] negative 15[01:20] 1 1/3 [01:20] - 1 1/3 [01:20] yea 15[01:23] cot = ? [01:23] how about you do it i check lol [01:23] cot is 1 over tan 15[01:23] cos/sin ? [01:23] yep [01:23] same thing [01:23] cos/sin or 1 over tan 15[01:24] tan a = -1 1/3 , csc a = 5/4 , sec a = 1 2/3 , cot a = -3/4 [01:25] sec a should be negative [01:25] yea i think all right 15[01:25] ya thats what i wrote down on paper sorry [01:25] except fro the negative [01:25] see, easy 15[01:26] ok so 15[01:26] cos > 0 , tan > 0 15[01:27] idk what quadrants are in the tan graph [01:28] 1st and 3rd [01:28] there is an easy way to remember - 15[01:29] MU7C_Ronaldo is ~MU7C_Rona@Swift-ABAADFAC.jetstream.xtra.co.nz * MU7C_Ronaldo 15[01:29] MU7C_Ronaldo on +#Genesis +#gkclan @#galvantic +#tusn @#warzone +#clan_eclipse 15[01:29] MU7C_Ronaldo using hades.de.eu.SwiftIRC.net Here, take this pomegranate 15[01:29] MU7C_Ronaldo has identified for this nick 15[01:29] MU7C_Ronaldo End of /WHOIS list. - [01:29] 1st quadrant, cos sin tan all over 0 [01:29] 2nd sin is over 0 [01:29] 3rd tan is over 0 [01:29] 4th cos is over 0 15[01:29] ver confuzzled 15[01:29] very [01:30] confuzzle? 15[01:30] confused lol 15[01:30] -> [MU7C_Ronaldo] TIME 15[01:30] [MU7C_Ronaldo TIME reply]: 2009-09-30 18:30:45 [01:31] ....... 15[01:31] where the hell 15[01:31] in the world 15[01:31] is it 6:30 pm [01:32] my place [01:32] lol [01:32] new zealand 15[01:32] o ok 15[01:33] 3rd and 4th sin is under 0 ? [01:33] yes 15[01:33] 2nd and 3rd cos is under 0 15[01:34] and 2nd and 4th tan is under 0 ? [01:34] yes [01:34] why don't you use my easy way-,- 15[01:34] well 15[01:34] i just understood ur easy way 15[01:34] and tried to clarify it 15[01:34] with the opposites of what u gave me [01:34] ASTC [01:35] all sin tan cos 15[01:35] o nice [01:36] my way is my teacher way tbh [01:36] i am in the top class, she is best teacher i reckno [01:36] reckon 15[01:39] sin a = square root of 3 / 2 , cos a = 1/2 so tan = square root of 3 ? [01:40] yes [01:40] thoguht they gonna ask what a is 15[01:43] cot = 1/2 / square root of 3 / 2 ? 15[01:43] how do u simplify dat [01:43] 1 over root 3 [01:44] coz both the bottom and top is divided by 2, thus, cancel 15[01:44] kk [01:46] or the easier way is [01:46] tan a is root 3 [01:46] cot a is 1 over tan a [01:46] so 1 over root 3 15[01:46] k 15[01:47] sec = 1 / root of 3 / 2 ? [01:48] k anotehr thing to teach you, if there is a fraction divided by the other fraction [01:48] use the rule top bottom bottom top [01:48] 1 is the top [01:48] roto 3 is the bottom [01:48] 2 is the top again 15[01:48] 2/ root of 3 ? [01:48] so multiply all the top and bottoms [01:48] yep thats right [01:48] 2 over root 3 15[01:49] csc = 2 15[01:49] ?> [01:49] no, csc is 1 over sin 15[01:49] i fot secant is 1 / sin ? 15[01:49] and cosecant = 1 / cos ? [01:50] nope [01:50] cosec <--3rd letter is s, 1over sin [01:50] sec, 3rd letter is c, 1 over cos [01:50] that's how i remember it 15[01:50] so csc= 2 / sq root of 3 ? 15[01:50] and sec =2 ? [01:51] yes [01:51] read the table [01:51] http://en.wikipedia.org/wiki/Sine#Right-angled_triangle_definitions 15[01:52] kk 15[01:52] i c 15[01:52] 1 more problem =o [01:53] go 15[01:54] ok so O = circle symbol thing 15[01:54] if sinO = .3 , find the value of sin + sin(O+2pi) + sin(O+4pi) = [01:57] lol circle symbol thing 15[01:57] so wait [01:57] as sine graph repeats itself every 2 pi [01:57] so those three are the same [01:57] so answer is 0.3+0.3+0.3= 0.9 15[01:58] circle symbol thing = .304692654 ? [01:58] i need to see what the symbol looks like 15[01:58] if sinO = .3 , sin ^-1 = .304692654 15[01:59] if sinO = .3 , sin^-1 of .3 = .304692654 15[01:59] * [01:59] is that O theta? 15[02:00] umm 15[02:00] the circle 15[02:00] with a line through the middle [02:00] a circle with a line across? [02:00] yea that just mean angle 15[02:00] k [02:00] theta is what it is called, well in english 15[02:00] so the angle = .304692654 correct ? [02:00] or greece? [02:00] lol [02:00] so anyway [02:01] (18:57:45) as sine graph repeats itself every 2 pi [02:01] (18:57:54) so those three are the same [02:01] (18:58:02) so answer is 0.3+0.3+0.3= 0.9 15[02:02] ok 15[02:02] well 15[02:02] the angle is .304692654 15[02:02] but ya 15[02:02] ur rite lol