// Program about sum, product, division, and riminder. # include using namespace std; int main() { int num1=0; // integers number1. int num2=0; // integers number2. float num3; // float number3. int sum1; // sum of the number1 and number2. int prod1; // product of the number1 and number2. int quot1; // division of the number1 and number2. int rmd; // riminder of the number1 and number2. float sum2; // sum of the number1 and number3. float prod2; // product of the number1 and number3 float quot2; // division of the number1 and number3 cout<< "enter the num1: "; cin >> num1; cout<< "enter the num2 (> 8): " ; cin >> num2 ; cout <<" num1" << '\t' << "num2" << '\t' << "num3" << '\t'; cout << "sum1" << '\t' << "sum2" << '\t'; cout << "prod1" << '\t' << "prod2" << '\t'; cout << "quot1" << '\t' << "quot2" << '\t'; cout << "rmd" << endl; cout << num1 << '\t' << num2 << '\t' << num3 << '\t'; cout << sum1 << '\t' << quot2 << '\t' << rmd << endl; // THIS IS THE PART OF CALCULATION num3 = num2 * 1.0; sum1 = num1 + num2 ; sum2 = num1 + num3 ; prod1 = num1 * num2 ; prod2 = num1 * num3 ; quot1 = num1 / num2 ; quot2 = num1 / num3 ; rmd = num1 % num2 ; cout << num1 << '\t' << num2 << '\t' << num3 << '\t'; cout << sum1 << '\t' << sum2 << '\t' << prod1 << '\t' << prod2 << '\t'; cout << quot1 <<'\t' << quot2 <<'\t' << rmd << endl; num1=num1 + 5; num2=num2 - 3; //PART OF CALCULATION ENDS HERE // What happen if you repeat the above part again ? but this time see the num1 is not the one you entered, its //the value after the num1+5 is //performed, so if you repeat this one more time like below what are the results //coming ? // THIS IS THE PART OF CALCULATION num3 = num2 * 1.0; sum1 = num1 + num2 ; sum2 = num1 + num3 ; prod1 = num1 * num2 ; prod2 = num1 * num3 ; quot1 = num1 / num2 ; quot2 = num1 / num3 ; rmd = num1 % num2 ; cout << num1 << '\t' << num2 << '\t' << num3 << '\t'; cout << sum1 << '\t' << sum2 << '\t'; cout << prod1 << '\t' << prod2 << '\t'; cout << quot1 << '\t' << quot2 << '\t'; cout << rmd << endl; num1=num1 + 5; num1=num1 + 5; num2=num2 - 3; num2=num2 - 3; // PART OF CALCULATION ENDS HERE return 0; }