function searchForOddPerfectNumber()
     var int n = 1     // arbitrary-precision integer
     loop {
         var int sumOfFactors = 0
         for factor from 1 to n - 1 {
             if factor is a factor of n then
                 sumOfFactors = sumOfFactors + factor
         }
         if sumOfFactors = n then
             exit loop
         n = n + 2
     }
     return